The emf and the internal resistance of a battery are as shown in the figure. If

Question

The emf and the internal resistance of a battery are as shown in the figure. If a current of 8.3 A is drawn from the battery when a resistor R is connected across the terminals ab of the battery, what is the power dissipated by the resistor R? The emf and the internal resistance of a battery are as shown in the figure (95V, 5O). If a current of 8.3 A is drawn from the battery when a resistor is connected across the terminals ab of the battery, what is the power dissipated by the resistor ? 790 W 440 W 620 W 700 W 530 W

Explanation / Answer

apply E = V-iR

E = 95-(8.3*5)

E = 53.5 V

now Power P = Vi

P = 53.5* 8,3

P = 444.5 Volts

option 2 it is

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