1)A person cannot see clearly closer than 2.0 m. What is the power of lens the p
ID: 1287812 • Letter: 1
Question
1)A person cannot see clearly closer than 2.0 m. What is the power of lens the person needs to see an object at 20 cm from eyes?
2)Of the following distances, which is the closest an object can be to a converging lens of focal length f and still give a real image?
0.49f
50 cm after the second lens
4)A single concave mirror is used to create an image of a 6.00-cm tall object that is located 35.0 cm away from the vertex of the mirror. If the magnitude of the radius of curvature for the mirror is 12.0 cm, what is the height of the image?
5)There is a piece of rock at the bottom of a 2.00-m deep pool of water. You are looking directly down on the rock from above the water surface. How far below the surface of the water the rock appears to you? Use refractive index of water as 1.33.
3f 2f 1.2f 0.8f0.49f
50 cm after the second lens
4)A single concave mirror is used to create an image of a 6.00-cm tall object that is located 35.0 cm away from the vertex of the mirror. If the magnitude of the radius of curvature for the mirror is 12.0 cm, what is the height of the image?
5)There is a piece of rock at the bottom of a 2.00-m deep pool of water. You are looking directly down on the rock from above the water surface. How far below the surface of the water the rock appears to you? Use refractive index of water as 1.33.
Explanation / Answer
1) (1/0.20) - (1/2) = P
P = 4.5 D
2) 1.2f
3) 10 cm after the second lens
4) 1.24 cm
5) 1.33/2 = -1/s'
s' = 1.5
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