A block of mass m1 = 1.10kg moving at v1 = 1.60m/s undergoes a completely inelas
ID: 1286924 • Letter: A
Question
A block of mass m1 = 1.10kg moving at v1 = 1.60m/s undergoes a completely inelastic collision with a stationary block of mass m2 = 0.600kg . The blocks then move, stuck together, at speed v2. After a short time, the two-block system collides inelastically with a third block, of mass m3 = 2.80kg , which is initially at rest. The three blocks then move, stuck together, with speed v3.(Figure 1) Assume that the blocks slide without friction.
A) Find v2v1, the ratio of the velocity v2 of the two-block system after the first collision to the velocity v1 of the block of mass m1 before the collision.
Express your answer numerically using three significant figures.
B)
Find v3v1, the ratio of the velocity v3 of the three-block system after the second collision to the velocity v1 of the block of mass m1 before the collisions.
Express your answer numerically using three significant figures.
A block of mass m1 = 1.10kg moving at v1 = 1.60m/s undergoes a completely inelastic collision with a stationary block of mass m2 = 0.600kg . The blocks then move, stuck together, at speed v2. After a short time, the two-block system collides inelastically with a third block, of mass m3 = 2.80kg , which is initially at rest. The three blocks then move, stuck together, with speed v3.(Figure 1) Assume that the blocks slide without friction. A) Find v2v1, the ratio of the velocity v2 of the two-block system after the first collision to the velocity v1 of the block of mass m1 before the collision. Express your answer numerically using three significant figures. B) Find v3v1, the ratio of the velocity v3 of the three-block system after the second collision to the velocity v1 of the block of mass m1 before the collisions. Express your answer numerically using three significant figures.Explanation / Answer
v2 = m1 . v1 / (m1 + m2)
v2 / v1 = m1 / ( m1 + m2)
v3 = m1 . v1 / ( m1 + m2 + m3 )
v3 / v1 = m1 / ( m1 + m2 + m3 )
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