The drawing shows a collision between two pucks on an air-hockey table. Puck A h

Question

The drawing shows a collision between two pucks on an air-hockey table. Puck A has a mass of 0.0330 kg and is moving along the x axis with a velocity of +4.60 m/s. It makes a collision with puck B, which has a mass of 0.0660 kg and is initially at rest. The collision is not head-on. After the collision, the two pucks fly apart with the angles shown in the drawing. Find the speed of (a) puck A and (b) puck B.

The drawing shows a collision between two pucks on an air-hockey table. Puck A has a mass of 0.0330 kg and is moving along the x axis with a velocity of +4.60 m/s. It makes a collision with puck B, which has a mass of 0.0660 kg and is initially at rest. The collision is not head-on. After the collision, the two pucks fly apart with the angles shown in the drawing. Find the speed of (a) puck A and (b) puck B

Explanation / Answer

It can be done simple by conserving momentum along x-axis and y-axis.
along x-axis :
initial momentum = (Mass of A)*(initial vel. of A)
Final momentum = (mass of A)*(final vel of A)*cos(65degrees) + (mass of B)*(final vel of B)*cos(37degrees)
Initial momentum = Final momentum

Along y-axis:
Initial momentum = 0
Final momentum = (mass of A)*(final vel of A)*sin(65deg). + (mass of B)*( vel of B)* sin(37deg)
Initial momentum = Final momentum

2 variables, 2 equations. Now you can easily solve it.

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