Exercise 8.13 A 3.00 tg stone is sliding to the right on a frictionless horizont

Question

Exercise 8.13 A 3.00 tg stone is sliding to the right on a frictionless horizontal surface at 4.00 m/s. When it is suddenly struck by an otiect that exerts a large horizontal force on it for a short period of time. The graph in the figure shows the magnitude of the force as a function of time. Part A What impulse does this force exert on the stone? Part B Just after the force stops acting. (find the magnitude of the stones velocity if the force acts to the right. Part C Just after the force stops acting. find the direction of the stone's velocity if the force acts to the right. to the right to the left Part D Just after the force stops acting. find the direction of the stone's velocity if the force acts to the left. Part E Just after the force stops acting, find the direction of the stone's velocity if the force acts to the left to the right to the left

Explanation / Answer

Part A)

Impulse = Ft

I = (2500)(1 X 10-3)

I = 2.5 Ns

Part B)

Impulse = change in momentum

Force to the right

2.5 = m(v - vo)

2.5 = 3(v - 4)

v = 4.83 m/s

Part C)

To the right

Part D)

Impulse = change in momentum

Force to the left

2.5 = m(v + vo)

2.5 = 3(v + 4)

v = 3.17 m/s

Part E)

Still to the right

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