In the apparatus shown in the figure , m1 = 13kg and the coefficients of static

Question

In the apparatus shown in the figure , m1 = 13kg and the coefficients of static and kinetic friction between m1 and the table are 0.67 and 0.34, respectively. Part A What mass of m2 will just barely set the system in motion?

Part B

After the system begins to move, what is the acceleration?

Express your answer using two significant figures.

In the apparatus shown in the figure , m1 = 13kg and the coefficients of static and kinetic friction between m1 and the table are 0.67 and 0.34, respectively. Part A What mass of m2 will just barely set the system in motion? Part B After the system begins to move, what is the acceleration? Express your answer using two significant figures.

Explanation / Answer

Let the tension in the rope be T

when the system is barely set into motion

Tension should over come the static friction on m1

Normal reaction on m1, N= m1g

static friction = .67 * N

T = .67 * 13 * 9.81 = 85.4451 N

this tension is provided by the gravitational force on m2

m2g = T = 85.4451

m2 = 8.71 kg

b)

after the system begins to move

m2g - T = m2a

T - .34 * m1g = m1a

soving the equations =>

m2g - m2a = m1a + .34 * m1g

a = 1.94 m/s^2

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.