Two straight parallel wires carry currents in opposite directions as shown in th

Question

Two straight parallel wires carry currents in opposite directions as shown in the figure. One of the wires carries a current of I2 = 10.5 A. Point A is the midpoint between the wires. The total distance between the wires is d = 11.2 cm. Point C is 4.95 cm to the right of the wire carrying current I2. Current I1 is adjusted so that the magnetic field at C is zero.

Calculate the value of the current I1.

Calculate the magnitude of the magnetic field at point A.

What is the force between two 1.47 m long segments of the wires?

Two straight parallel wires carry currents in opposite directions as shown in the figure. One of the wires carries a current of I2 = 10.5 A. Point A is the midpoint between the wires. The total distance between the wires is d = 11.2 cm. Point C is 4.95 cm to the right of the wire carrying current I2. Current I1 is adjusted so that the magnetic field at C is zero. Calculate the value of the current I1. Calculate the magnitude of the magnetic field at point A. What is the force between two 1.47 m long segments of the wires?

Explanation / Answer

at point C, magnetic field Due to i1   must be = magnetic rield due to i2

so u0i1/(2pi(0.112+0.0495) = uoi2/(2pi (.0495)

so i1 = (10.5*0.1615)/ 0.0495

i1 = 34.25 Amps

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Bnet At A = B1+B2

Bnet = 4pie-7 * ( 10.5+34.25)/(2pi *(0.112/2)

Bnet = 1.598 *10^-4 T is the mag field at A

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apply force F = uoi1i2L/2piD

F = 4pie-7 * 10.2* 34.25*1.47/(2pi* 0.112)

F   = 9.170 *10^-4 N

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