To apply the law of conservation of energy to an object launched upward in Earth

Question

To apply the law of conservation of energy to an object launched upward in Earth's gravitational field.

In the absence of nonconservative forces such as friction and air resistance, the total mechanical energy in a closed system is conserved. This is one particular case of the law of conservation of energy.

In this problem, you will apply the law of conservation of energy to different objects launched from Earth. The energy transformations that take place involve the object's kinetic energy K=(1/2)mv2 and its gravitational potential energy U=mgh. The law of conservation of energy for such cases implies that the sum of the object's kinetic energy and potential energy does not change with time. This idea can be expressed by the equation

Ki+Ui=Kf+Uf,

where "i" denotes the "initial" moment and "f" denotes the "final" moment. Since any two moments will work, the choice of the moments to consider is, technically, up to you. That choice, though, is usually suggested by the question posed in the problem.

First, let us consider an object launched vertically upward with an initial speed v. Neglect air resistance. Using conservation of energy, find the maximum height hmax to which the object will rise. Express your answer in terms of v and the magnitude of the acceleration of gravity g.

h(max)=?????

Explanation / Answer

hmax= v^2/2g

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