Show work please A 516 kg mass is sliding on a horizontal fric tionless surface

Question

Show work please

A 516 kg mass is sliding on a horizontal fric tionless surface with a speed of 9.6 m/s when it collides with a 84 kg mass initially at rest as shown. masses stick together and slide up a frictionless track at 60 from horizontal. 9.6 m/s 84 kg 516 kg 60 What is the speed of the two blocks imme- diately after the collision? The acceleration due to gravity is 9.8 m/s2 Answer in units of m/s After the collision, the masses slide up the incline. 600 kg To what maximum height h above the hor izontal surface will the masses slide? Answer in units of m

Explanation / Answer

Conservation of momentum gives

mu'+Mv'=(m+M)V

0+516*9.6=600*V

V=8.256 m/s after the collision

Now , conservation of energy

(m+M)gh =(1/2)(m+M)V2

h=V2/2g=8.2562/(2*9.8)=3.47 m

h=3.47 m

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