1. Two straight parallel wires carry currents in opposite directions as shown in
ID: 1284390 • Letter: 1
Question
1. Two straight parallel wires carry currents in opposite directions as shown in the figure. One of the wires carries a current of I2 = 11.1 A. Point A is the midpoint between the wires. The total distance between the wires is d = 10.1 cm. Point C is 5.89 cm to the right of the wire carrying current I2. Current I1 is adjusted so that the magnetic field at C is zero. Calculate the value of the current I1.
2. Calculate the magnitude of the magnetic field at point A.
3. What is the force between two 1.35 m long segments of the wires?
1. Two straight parallel wires carry currents in opposite directions as shown in the figure. One of the wires carries a current of I2 = 11.1 A. Point A is the midpoint between the wires. The total distance between the wires is d = 10.1 cm. Point C is 5.89 cm to the right of the wire carrying current I2. Current I1 is adjusted so that the magnetic field at C is zero. Calculate the value of the current I1. 2. Calculate the magnitude of the magnetic field at point A. 3. What is the force between two 1.35 m long segments of the wires?Explanation / Answer
at point C, magntic fiedl due to i1 = magnetic fiedl due to i12
so uoi1/2piR1 = Uoi2/2piR2
i1/((0.101+0.0589) = 11.1/(0.0589)
i2 = 0.1599 * 11.1/(0.0589))
i2 = 30.133 Amps
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2. magnetic field at mid pointB = uo(i1+i2)/2piD
B = 4pie-7*(11.1+30.13)/(2*3.14*0.0505)
BNet = 1.632*10^-4 T
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Fnet = u0i1i2L/(2pi D)
F = 4pie-7 * 11.1* 30.13* 1.35/(2pi*0.101)
F = 8.9*10^-4 N
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