One man is standing on one foot while holding the other leg up, at 90 degrees fl
ID: 1284275 • Letter: O
Question
One man is standing on one foot while holding the other leg up, at 90 degrees flexion as shown the figure. The leg is 50 cm long, pivots at the knee joint, and has a total mass of 5 kg, with the center of gravity at 15 cm bellow the knee joint. The force holding the leg up is provided by a tendon attached to the lower let at 4 cm bellow the knee. What is the tension in the tendon to keep the leg in position? What is the magnitude and direction of the force at the knee joint?
One man is standing on one foot while holding the other leg up, at 90 degrees flexion as shown the figure. The leg is 50 cm long, pivots at the knee joint, and has a total mass of 5 kg, with the center of gravity at 15 cm bellow the knee joint. The force holding the leg up is provided by a tendon attached to the lower let at 4 cm bellow the knee. What is the tension in the tendon to keep the leg in position? What is the magnitude and direction of the force at the knee joint?Explanation / Answer
sum torque about knee joint
5*9.81*15 - F*4 = 0
F tendon=184 N
sum forces in the y
-5*9.81 +184+ F =0
F knee joint= -135 N
so 135 N downwards
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