An electric ceiling fan is rotating about a fixed axis with an initial angular v

Question

An electric ceiling fan is rotating about a fixed axis with an initial angular velocity magnitude of 0.200rev/srev/s . The magnitude of the angular acceleration is 0.906rev/s2rev/s^2 . Both the the angular velocity and angular accleration are directed clockwise. The electric ceiling fan blades form a circle of diameter 0.720mm . What is the tangential speed of a point on the tip of the blade at t=.204 s?

What is the magnitude a of the resultant acceleration of a point on the tip of the blade at t=.204s?

useful info:

Express your answer numerically in revolutions per second. (0.385)

SubmitHintsMy AnswersGive UpReview Part

Correct

Part B

Express the number of revolutions numerically. (5.97*10^-2)

0.385

SubmitHintsMy AnswersGive UpReview Part

Correct

Part C

Express your answer numerically in meters per second.

5.9710?2

SubmitHintsMy AnswersGive UpReview Part

0.385

rev/s An electric ceiling fan is rotating about a fixed axis with an initial angular velocity magnitude of 0.200rev/srev/s . The magnitude of the angular acceleration is 0.906rev/s2rev/s^2 . Both the the angular velocity and angular accleration are directed clockwise. The electric ceiling fan blades form a circle of diameter 0.720mm . What is the tangential speed of a point on the tip of the blade at t=.204 s? What is the magnitude a of the resultant acceleration of a point on the tip of the blade at t=.204s? useful info: Compute the fan's angular velocity magnitude after time 0.204s rm rev SubmitHintsMy AnswersGive UpReview Part s ? Express your answer numerically in meters per second. 5.97½10?2 rev t = 0.204s v_tan(t) of a point on the tip of the blade at time t rm rev/s SubmitHintsMy AnswersGive UpReview Part Correct Part C What is the tangential speed vtan(t) s from Part A? Express the number of revolutions numerically. (5.97*10^-2) 0.385 rev/s s has passed. Express your answer numerically in revolutions per second. (0.385) SubmitHintsMy AnswersGive UpReview Part Correct Part B Through how many revolutions has the blade turned in the time interval 0.204s

Explanation / Answer

A)

Use the formula v = vi + at:

v = vi + at
v = 0.200 + 0.906 * 0.204
v = 0.384 rev/s

B)

Since we found the ending velocity in Part A, we can use the following formula. The unrounded ending speed was 0.384rev/s:

vf^2 = vi^2 + 2a(?x)
0.384^2 = 0.200^2 + 2 * 0.906 * x
x = 0.0593 rev

C)

Since the diameter of the fan is 0.720 m, it

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.