1. A 2.05 kg ball is attached to the bottom end of a length of 9 lb (40.1 N) fis

Question

1. A 2.05 kg ball is attached to the bottom end of a length of 9 lb (40.1 N) fishing line. The top end of the fishing line is held stationary. The ball is released from rest while the line is taut and horizontal (? = 90.0

1. A 2.05 kg ball is attached to the bottom end of a length of 9 lb (40.1 N) fishing line. The top end of the fishing line is held stationary. The ball is released from rest while the line is taut and horizontal (? = 90.0°). At what angle ? (measured from the vertical) will the fish line break? 2. As shown in the figure below, a 2.25-kg block is released from rest on a ramp of height h. When the block is released, it slides without friction to the bottom of the ramp, and then continues across a surface that is frictionless except for a rough patch of width 15.0 cm that has a coefficient of kinetic friction ?k = 0.650. Find h such that the block's speed after crossing the rough patch is 3.10 m/s. ___ m

Explanation / Answer

1.Max Vert Force from ball = 2.05 x 9.81 = 20.0 N

Draw a diagram and you get a triangle. The angle the string makes at breaking = ?

Horizontal component of that force = 20 cos ?

Max that force can be = 40.1 N

Solve the triangle:

mg / 40.1 = sin ?

? = sin^-1 (20 / 40.1)

? = 29.91 degrees

Draw out the triangle of forces and then it is simple geometry. You must learn to do these yourself or you will not succeed.

2.work enegy theorm

2.25*9.81*h-.65*2.25*9.81=.5*2.25*3.10^2

h=1.13m

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.