can u plz help me with this? A box rests on top of a flat bed truck. The box has

Question

can u plz help me with this?

A box rests on top of a flat bed truck. The box has a mass of m = 19 kg. The coefficient of static friction between the box and truck is mu s = 0.82 and the coefficient of kinetic friction between the box and truck is mu k = 0.67. The truck accelerates from rest to Vf = 15 m/s in t = 13 s (which is slow enough that the box will not slide). What is the acceleration of the box? m/s2 In the previous situation, what is the frictional force the truck exerts on the box? N What is the maximum acceleration the truck can have before the box begins to slide? m/s2 Now the acceleration of the truck remains at that value, and the box begins to slide. What is the acceleration of the box? m/s2 With the box still on the truck, the truck attains its maximum velocity. As the truck comes to a stop at the next stop light, what is the magnitude of the maximum deceleration the truck can have without the box sliding? m/s2

Explanation / Answer

1.accn of box =v/t=15/13=1.15m/s^2

2.frictional force=ma=19*1.15=21.92N

3.max accn=usg=0.82*9.81=8.04m/s^2

4.accn=(uk)g=(0.67)*9.81=6.57m/s^2

5.max deccn=usg=0.82*9.81=8.04m/s^2

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