The 2 kg block slides down a frictionless curved ramp, starting from rest at a h
ID: 1282673 • Letter: T
Question
The 2 kg block slides down a frictionless curved ramp, starting from rest at a height of h = 3 m. The block then slides d = 13 m on a rough horizontal surface before coming to rest.
1)
(a) What is the speed of the block at the bottom of the ramp?
m/s
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2)
(b) What is the energy dissipated by friction?
J
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3)
(c) What is the coefficient of friction between the block and the horizontal surface?
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Explanation / Answer
PE at top = KE at bottom
mgh = 1/2 mv2
gh = 1/2 v2
v = sqrt(2gh) = sqrt ( 2 * 9.8 * 3)
v = 7.67 m/s
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b) a = v2- v02/ 2 s = 0 - 7.672/ 2 * 13
a = -2.26 m/s2
W = m a d = 2 * 2.26 * 13
= 58.76 J
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mu = a / g = 2.26 / 9.8
= 0.231
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