A uniform electric field has magnitude e and is directed in the negative x direc

Question

A uniform electric field has magnitude e and is directed in the negative x direction. the potential difference between point a (at x= 0.55m ) and point b (at x= 0.85m ) is 250v.

1) Which point, a or b, is at the higher potential?

2) Calculate the value of E.

Express your answer using two significant figures.

3) A negative point charge q=?0.200?C is moved from b to a. Calculate the work done on the point charge by the electric field.

Express your answer using two significant figures.

4) A negative point charge q=?0.200?C is moved from b to a. Calculate the work done on the point charge by the electric field.

Express your answer using two significant figures.

Explanation / Answer

_____________________________________

A uniform electric field has magnitude E and is directed in the negative x direction.

As potential falls in the direction of field, the potential is increasing on positive x axis

The potential difference between point a (at x= 0.550 m) and point b (at x= 0.850 m) is 250 V.

1. Point b is at the higher potential
______________________
E =-(Vb-Va)/[0.850-0.550]

E =250 /0.300

E =833.33 N/C
_______________________-------

Work = qV = -0.2*10^-6*250

work = -5*10^-5 J

the work done on the point charge by the electric field is -5*10^-5 J
__________________________

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