Two identical balls are thrown vertically upward. The second ball is thrown with

Q: Two identical balls are thrown vertically upward. The second ball is thrown with

Use conservation of energy: Forfirst 1/2 mv^2 = mgh ---> h = v^2/(2g) Now let v --> 2v, then h --> h' = 2v^2/g So second ball travels 4 times hihger E. The maximum height of the second ball is four times that of the first ball

ID: 1282491 • Letter: T

Question

Two identical balls are thrown vertically upward. The second ball is thrown with an initial speed that is twice that of the first ball. How does the maximum height of the two balls compare?

A. The maximum height of the second ball is eight times that of the first ball.

B. The maximum height of the second ball is two times that of the first ball.

C. The maximum height of the second ball is 1.41 times that of the first ball.

D. The maximum heights of the two balls are equal.

E. The maximum height of the second ball is four times that of the first ball.

Explanation / Answer

Use conservation of energy:

Forfirst 1/2 mv^2 = mgh ---> h = v^2/(2g)

Now let v --> 2v, then h --> h' = 2v^2/g

So second ball travels 4 times hihger

E. The maximum height of the second ball is four times that of the first ball

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Two identical balls are thrown vertically upward. The second ball is thrown with

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Two identical balls are thrown vertically upward. The second ball is thrown with

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