An object with mass 60 kg moved in outer space. When it was at location < 10, -2

Question

An object with mass 60 kg moved in outer space. When it was at location < 10, -23, -5 > its speed was 5 m/s. A single constant force < 250, 450, -170 > N acted on the object while the object moved from location < 10, -23, -5 > m to location < 15, -17, -8 > m. Then a different single constant force < 150, 240, 160 > N acted on the object while the object moved from location < 15, -17, -8 > m to location < 19, -22, -2 > m. What is the speed of the object at this final location?

Explanation / Answer

force=F=ma=mv/t=mv/(d/v)=mv2/d

in the second case we are given F,m and d, we can find the velocity v

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