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A boy pulls upward with a force of 35N at an angle of 30.0 degrees on a 30.0 kg

ID: 1282424 • Letter: A

Question

A boy pulls upward with a force of 35N at an angle of 30.0 degrees on a 30.0 kg box as shown. If a frictional force of 15N is acting against the pull:

a.) what is the acceleration of the box?

b.) what is the normal force?

The picture shows 25N, but it is suppose to be 35N.

A boy pulls upward with a force of 35N at an angle of 30.0 degrees on a 30.0 kg box as shown. If a frictional force of 15N is acting against the pull: a.) what is the acceleration of the box? b.) what is the normal force? The picture shows 25N, but it is suppose to be 35N.

Explanation / Answer

35*cos30 - 15 = 30*a

a = 0.510 m/s^2


N = 30*9.8 - 35sin30 = 276.5

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