The two metal objects in the figure have net charges of +63 pC and -63 pC, which
ID: 1282333 • Letter: T
Question
The two metal objects in the figure have net charges of +63 pC and -63 pC, which result in a 18 V potential difference between them. (a) What is the capacitance of the system? (b) If the charges are changed to +290 pC and -290 pC, what does the capacitance become? (c) What does the potential difference become?
(a) Number Units The two metal objects in the figure have net charges of +63 pC and -63 pC, which result in a 18 V potential difference between them. (a) What is the capacitance of the system? (b) If the charges are changed to +290 pC and -290 pC, what does the capacitance become? (c) What does the potential difference become? (a) Number Units (b) Number Units (c) Number UnitsExplanation / Answer
a. apply charge Q = CV
C = Q/V = 63e-12/18 = 3.5 pF
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if Q = 290 pC
C = 290e-12/18 = 16.11 pF
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V = Q/C = 16.11/3.5
V = 4.603 Volts
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