In each of the two free-body diagrams, the forces are acting on a 2.4kg object.

Question

In each of the two free-body diagrams, the forces are acting on a 2.4kg object.

a)For diagram (Figure 1) , find the value of ax, the x-component of the acceleration.

b)For diagram the part A, find the value of ay, the y-component of the acceleration.

c)For diagram (Figure 2) , find the value of ax, the x-component of the acceleration.

d)For diagram the part C, find the value of ay, the y-component of the acceleration.

figure 1 figure 2

In each of the two free-body diagrams, the forces are acting on a 2.4kg object. a)For diagram (Figure 1) , find the value of ax, the x-component of the acceleration. b)For diagram the part A, find the value of ay, the y-component of the acceleration. c)For diagram (Figure 2) , find the value of ax, the x-component of the acceleration. d)For diagram the part C, find the value of ay, the y-component of the acceleration. figure 1 figure 2

Explanation / Answer

(A) FROM THE FREE BODY DIAGRAM FIG(1):

NET FORCE IN X DIRECTION =F*=2N-4N = -2N (-VE SIGN MEANS IN -VE X DIRECTION)

THERFORE

Ax=-2N/2.4Kg = -.833m/sec^2

similarly ,

NET FORCE IN Y DIRECTION = 3N-3N =0N

HENCE THE ACCELERATION IN Y DIRECTION =Ay=0

(B)

for fig(2): ACCELERATION IN X DIRECTION=(4N-2N)/2.4 = +.83333 m/sec^2

ACCELERATION IN Y DIRECTION = (3N-3N)/2.4 = 0m/sec^2

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