A object of mass 3.00 kg is subject to a force Fx that varies with position as i

Question

A object of mass 3.00 kg is subject to a force Fx that varies with position as in the figure (a) Find the work done by the force on the object as it moves from x = 0 to x = 4.00 m Correct: Your answer is correct. J (b) Find the work done by the force on the object as it moves from x = 5.00 m to x = 7.00 m Incorrect: Your answer is incorrect. Your response differs from the correct answer by more than 100%. J (c) Find the work done by the force on the object as it moves from x = 11.0 m to x = 15.0 m. (d) If the object has a speed of 0.500 m/s at x = 0, find its speed at x = 5.00 m and its speed at x = 15.0 m.

Explanation / Answer

a)

Work Done

W=Area under the curve from X=0 to X=4

W=(1/2)*2.5*4= 5 J

b)

W=Area under the curve from X=5 to X=7

W=(7-5)*3 =6 J

c)

Work Done

W=Area under the curve from X=11 to X=15

W=(1/2)*2.5*(15-11)= 5 J

d)

Work done

W=Area under the curve from X=0 toX=5

W=(1/2)*3*5=7.5 J

at X=5 m

W=(1/2)m(V22-V12)

7.5=(1/2)*3*(V22-0.52)

V2=2.29 m/s

Work Done form X=0 to X=15 m

W=(1/2)*5*3+3*5+(1/2)*5*3 =30

W=(1/2)m(V22-V12)

30=(1/2)*3*(V22-0.52)

V2=4.5 m/s

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