A) Find the current in each resistor. B) Find the total current through the batt

Question

A) Find the current in each resistor.
B) Find the total current through the battery.
C) Find the voltage across each resistor.
D) Find the power dissipated in each resistor.
E) Which resistor dissipates the most power, the one with the greatest resistance or the one with the least resistance? Explain why this should be.

Three resistors having resistances of R1 = 1.69 omega respectively, are connected in parallel to a 28.2V battery that has negligible internal resistance. A) Find the current in each resistor. B) Find the total current through the battery. C) Find the voltage across each resistor. D) Find the power dissipated in each resistor. E) Which resistor dissipates the most power, the one with the greatest resistance or the one with the least resistance? Explain why this should be. omega , and R3 = 4.95 omega , R2 = 2.55

Explanation / Answer

A)

I1=V/R1=16.686A

I2=V/R2=11.06A

I3=V/R3=5.697A

B)

I=I1+I2+I3=33.442A

C)

V1=V2=V3=28.2V

D)

P1=V^2/R1=470.556W

P2=V^2/R2=311.86W

P3=V^2/R3=160.655W

E)

The one with the least resistance dissipates more power as when V is constant then Power is inversely proportional to R.

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