While a roofer is working on a roof that slants at = 36.0degrees above the horiz

Question

While a roofer is working on a roof that slants at = 36.0degrees above the horizontal, he accidentally nudges his m = 8.50kg toolbox, causing it to start sliding downward, starting from rest. A frictional force of magnitude fk = 22.0N acts on the toolbox as it slides. If the box starts d = 4.25m from the lower edge of the roof, how fast v will the toolbox be moving just as it reaches the edge of the roof? Assume that the acceleration due to gravity is g = 9.80m/s2. The initial and final states of the toolbox are illustrated in the figure. Identify the initial speed vi of the toolbox and the vertical distance h through which the toolbox moves. I keep getting the same answer for h and im wrong.

Explanation / Answer

This problem is not that hard but it's a pain to solve
sine(36)*83.3 -22= let's call it x since I don't have a calculator but this is the force on the box along the roof.

x = 26.963 N
the box's weight is about 8.5kg
the weight can determine the acceleration. 26.963/8.5kg = 3.172 m/s^2
vf^2- vi^2= 2*a* delta x
vf^2= 2 *3.172* ( 4.25m)

     vf = 5.19 m/s

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.