3. Some years in the future (for most members of the class) your daughter has a

Question

3. Some years in the future (for most members of the class) your daughter has a paper route. There is one
particularly demanding customer on the route who insists that the paper be delivered directly to her kitchen
table. One morning you are helping your child with the paper route when the two of you nd that the door
of this customer's house is locked. But you notice that a skylight in the kitchen roof is open. As shown
in Figure 1(b) the skylight is 4.00 m above the ground. The center of the table is 6.00 horizontally from

Please do Q 3 very clear.

the point directly under the skylight. You tell your daughter (who is the best infielder in her class because of her precise control of the ball), "Sweetie, just give me a moment and I can calculate how you need to throw the paper to get it through the skylight and onto the table." Of course she rolls her eyes at you while you do the calculation. At last you finish and say, "Stand the same distance from the skylight that the table is, and throw underhand so that the release point is at about the same height as the table top. Now throw with..." (what angle and initial speed does your daughter need to throw with to get the paper in the middle of the table?) Additional questions for practice (will not be marked) Knight: CQ4.1, CQ4.4, P4.7, P4.10 (Yes, I know the answer isn't in the back of the book. But I'm pretty

Explanation / Answer

so need to get it through the skylight

first do y direction

v^2 = v0y^2 + 2 a y

0 = v0y^2 - 2*9.81*(4-1)

v0y = sqrt(2*9.81*3)= 7.67 m/s

vy = v0y + a t

0 = 7.67 - 9.81*t

t=0.782 s

now x direction

x = v0x t

v0x = 6/0.782= 7.67 m/s

so speed = sqrt(7.67^2 + 7.67^2) = 7.67 m/s

direction = 45 degrees

Related Questions

Navigate

• Browse (All)
• Browse 3
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.