Question15 It is proposed that future space stations create an artificial gravit

Question

Question15
It is proposed that future space stations create an artificial gravity by rotating. Suppose a space station is constructed as a 1600-m-diameter cylinder that rotates about its axis. The inside surface is the deck of the space station.
Part A
What rotation period will provide "normal" gravity?
Express your answer with the appropriate units.
ANSWER:

Question 16
A 1000kg car pushes a 2200kg truck that has a dead battery. When the driver steps on the accelerator, the drive wheels of the car push against the ground with a force of 5000N . Rolling friction can be neglected.
Part A
What is the magnitude of the force of the car on the truck?
Express your answer to two significant figures and include the appropriate units.
ANSWER:

Part B
What is the magnitude of the force of the truck on the car?
Express your answer to two significant figures and include the appropriate units.
ANSWER:

Part B
Assume that segment R exerts a force of magnitude T on segment L. What is the magnitude FRL of the force exerted on segment R by segment L?
Give your answer in terms of T and other constants such as g.
You did not open hints for this part.
ANSWER:

Part D
Now consider a rope that, unlike those usually studied in mechanics problems, actually has a significant mass m. The tension at the right end of this rope is T2 and that at the left end is T1. The rope has an accelerationarope to the right.
Complete the following equation for the force on the section of the rope of mass m, taking the positive direction to be to the right.
Give your answer in terms of T1, T2, and constants such as g.
You did not open hints for this part.
ANSWER:

Part E
Which of the following phrases, if they appear in a problem, allow you to assume that T2=T1 in a horizontally oriented rope?

ANSWER:
Which of the following phrases, if they appear in a problem, allow you to assume that in a horizontally oriented rope?

Explanation / Answer

Question 15) centrip acc = v2 / r

v = sqrt [gr] = sqrt [9.8*800] = 88.5 m/s

2 pi r = 2pi * 800 m = 5026.5 meters

time = dist / speed = 5026.5 / 88.5 m/s

= 56.79 s

--------------------------------------------

Question 16) acceleration of car & truck system = F/m = [ 5000 / (2200 + 1000) ]

a = 1.56 m/s

Related Questions

Navigate

• Browse (All)
• Browse Q
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.