Please show all work. The equation of a transverse wave traveling along a very l

Question

Please show all work.

The equation of a transverse wave traveling along a very long string is y = 3.41 sin(0.0840 Pi x +6.39 Pi t), where x and y are expressed in centimeters and t is in seconds. Determine (a) the amplitude, (b) the wavelength, (c) the frequency, (d) the speed, and (e) the maximum transverse speed of a particle in the string. (f) What is the transverse displacement at x = 7.90 cm when t = 0.722 s? Give your answers in centimeter-based where applicable. (a) Number Units (b) Number Units (C) Number Units (d) Number Units (e) Number Units (f) Number Units

Explanation / Answer

a) 3.41 cm

b) wavelenght L = 2pi/0.0840 pi = 23.80 cm

c) freq f= 6.39 pi/2pi = 3.195 Hz

d) speed v = w/k = 6.39 pi/ 0.084 pi = 76 cm/s

e) maxium trans spedd = wA = 6.39 pi*3.41 = 68.4 cm/s

f) y = -2.59 cm

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