(1) During a baseball game a batter hits a popup to a fielder 82meters away. The

Question

(1) During a baseball game a batter hits a popup to a fielder 82meters away. The acceleration of gravity is 9.8 m/s2 .If the ball remains in the air for 5.8 s, how high does it rise? Answer in m.

(2) A 0.56 kg rock is projected from the edge of the top of a building with an initial velocity of 8.33 m/s at an angle 52? above the horizontal. Due to gravity, the rock strikes the ground at a horizontal distance of 11.5 m from the base of the building. Building

How tall is the building? Assume the ground is level and that the side of the building is vertical. The acceleration of gravity is 9.8 m/s^2

.Answer in units of m

Explanation / Answer

1) X = Vx*T======Vx = 82/5.8 = 14.13 m/s

T = 2*Vy/g=======> Vy = T*g/2 = 28.42

H = Vy^2/2g = 2.01^2/(2*9.8) = 41.21m

2)

X = Vx*T ========> T = X/Vx = 11.5/(V*cos52) = 11.5/(8.33*cos52) = 2.24s

-h = Vy*T - 0.5*g*T^2

-h = (8.33*sin52*2.24)-4.9*2.24^2 = -9.88m

h = 9.88m

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