1. Generally peaking, a beam of electrons within an oscilloscope is controlled _

Question

1. Generally peaking, a beam of electrons within an oscilloscope is controlled ______________ by oscillating input voltage and __________________ by a time sweep. vertically, vertically horizontally, vertically vertically, horizontally horizontally, horizontally 2. Let's say that the time sweep dial is set to 0.5 milliseconds per division. How many seconds is each division? 3. The scope screen is divided into 10 major divisions across and 10 major divisions up (or down). Each minor division is worth _______ of the major division? 0.4 1 1/3 1/2 0.2 The next two questions reference the picture below. 4. One cycle (period) above ends a little past ____ major divisions? 5 4.3 26 23 4.6 5. Each division (by division, we mean by default, a major division.) in the above picture is worth 2ms. What is the period (in seconds) of this signal? 0.0023 s 2.3 s 4.6 s 0.0092 s 9.2 s 0.0046 s 6. Frequency is 1 over the period. the same as the period. seconds per cycle. The next two questions reference the picture below. 7. How many periods are there under the colored bracket in the picture above? There are periods. Type a number in digits. ie. 10 or 15.3 are two examples. 8. How many time divisions are covered by those same periods? 37 7.2 39 7.4 Please Note! The two pictures above are of the same frequency. The top one is sampling the data at 2ms per division. The lower picture is sampling at 5ms per division. 9. What is the frequency according to the second picture (of the two above)? Hz (To the nearest integer.) The left picture above is a lissajou figure with frequencies (y:x) of 1 to 2. It bounces once up and down while it bounces twice side to side. The right hand picture is a 2 to 1 because it bounces twice vertically for every single side to side bounce. 10. What is the ratio (y:x) for the lissajou figure below? 3 to 2 3 to 5 2 to 3 5 to 3

Explanation / Answer

vertical horizontal 0.0005 0.2 4.6 .0092 1/period 4 7.4 27 2 to 3

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