1. Initially, the switch in the figure to the right is open and the capacitor is

Question

1. Initially, the switch in the figure to the right is open and the capacitor is uncharged. How much charge flows through the switch after the switch is closed for a while?

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2.

a. What is the electric potential at point A in the figure above?

b. What is the potential energy of a proton at point A?

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3. What is the emf of a battery that does 0.60 J of work to transfer 0.050 C of charge from the negative to the positive terminal?

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4. A wire with resistance R is connected to the terminals of a 6.0 V battery. What is the potential
difference ?V between the ends of the wire and the current I through it if the wire has the
following resistances?

a. 1.0 ?

b. 2.0 ?

c. 3.0 ?

Explanation / Answer

1.

Charge

Q=Capacitance*Voltage =1.5*10

Q=15 uC or 15*10^-6 C

2.

a)

Electric Potential at point A

VA=V1+V2+V3 =KQ1/r1 +KQ2/r2 +KQ3/r3

VA=(9*10^9)[(-5/0.04)+(5/0.02)+(10/sqrt[0.04^2+0.02^2])

VA=3137.5Volts

b)

Charge of proton q=1.6*10^-19 C

Electrical Potential energy is

UA=qV =(1.6*10^-19)(3137.5) =5.02*10^-16 J

3)

Work done =charge *Voltage

W=q*V

=>V=W/q =0.6/0.05 =12 Volts

4)

Potential difference at the ends of wire is

dV=6 Volts

For 1 ohms =>I=V/R =6/1 =6 A

For 2 ohms =>I=6/2 =3 A

For 3 ohms =>I=6/3=2 A

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