A car starting at x = 52 m accelerates from rest at a constant rate of 8 m/s 2 .

Question

A car starting at x = 52 m accelerates from rest at a constant rate of 8 m/s2.

1)

(a) How fast is it going after 10 s?
m/s

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2)

(b) How far has it gone (from x = 0) after 10 s?
m

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3)

(c) What is its average velocity for the interval 0 < t < 10 s?
m/s

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Explanation / Answer

1) v = u + a*t

= 0 + 8*10

= 80 m/s

2) x = 52 + u*t + 0.5*a*t^2

= 52 + 0 + 0.5*10*8^2

= 372 m

3) u = 0, v = 80 m/s

a_avg = (u+v)/2

= (0+80)/2

= 40 m/s

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