----Having trouble with this physics homework. Was able to get parts of it but s
ID: 1274029 • Letter: #
Question
----Having trouble with this physics homework. Was able to get parts of it but struggling with the rest. Can you please explain with the answer please. Thank You So MUCH!!
A soft tennis ball is dropped onto a hard floor from a height of 1.95 m and rebounds to a height of 1.51 m.
(a) Calculate its velocity just before it strikes the floor.
m/s
(b) Calculate its velocity just after it leaves the floor on its way back up.
5,443 m/s
(c) Calculate its acceleration during contact with the floor if that contacts last 3.50 ms.
(d) How much did the ball compress during its collision with the floor, assuming the floor is absolutely rigid?
m
+++++++++An express subway train passes through an underground station. It enters at t = 0 with an initial velocity of 22.0 m/s and decelerates at a rate of 0.150 m/s2 as it goes through. The station in 220 m long.
(a) How long is the nose of the train in the station?
10.40s
(b) How fast is it going when the nose leaves the station?
20.43m/s
(c) If the train is 130 m long, at what time t does the end of the train leave the station?
s
(d) What is the velocity of the end of the train as it leaves?
m/s
Explanation / Answer
Let:
Vd = velocity just before it strikes the floor; let its value be negative.
Vu = just after it leaves the floor on its way back up; its value will then be positive
Sd = the distance it falls = 1.95m
Su = the distance it rebounds = 1.51m
(a)Calculate its velocity just before it strikes the floor
Using Equations of Motion, we know that:
(1) Sd =
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