Problem 23.29 The figure( Figure 1 ) shows a current-carrying wire and a circuit

Question

Problem 23.29

The figure(Figure 1) shows a current-carrying wire and a circuit containing a resistor R.

Part A

If the current in the wire is constant, is the induced current in the circuit clockwise, counterclockwise, or zero?

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Correct

Part B

Explain.

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Part C

If the current in the wire increases, is the induced current in the circuit clockwise, counterclockwise, or zero?

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Part D

Explain.

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Figure 1 of 1

Problem 23.29

The figure(Figure 1) shows a current-carrying wire and a circuit containing a resistor R.

Part A

If the current in the wire is constant, is the induced current in the circuit clockwise, counterclockwise, or zero?

If the current in the wire is constant, is the induced current in the circuit clockwise, counterclockwise, or zero? clockwise counterclockwise zero

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Correct

Part B

Explain.

Essay answers are limited to about 500 words (3800 characters maximum, including spaces).

3800 Character(s) remaining

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Part C

If the current in the wire increases, is the induced current in the circuit clockwise, counterclockwise, or zero?

If the current in the wire increases, is the induced current in the circuit clockwise, counterclockwise, or zero? clockwise counterclockwise zero

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Correct

Part D

Explain.

Essay answers are limited to about 500 words (3800 characters maximum, including spaces).

3800 Character(s) remaining

SubmitMy AnswersGive Up

Provide FeedbackContinue

JUST ANSWER ESSAY QUESTIONS PLEASE

Figure 1 of 1

Explanation / Answer

a. as we know dat

|e| = |delta phi|/|dt|

and phi = B.A = |B|Acos theta = |B|A

hence

|e| = |delta(|B|A)/delta t|

a. The Current in the circuit ll be ZERO...

b. Since area is constant, hence flux can be varied only be chnbigng the magnetic field. and we know dat magnetic field does not changes when the current in a long wire is constant.
hence there ll be no induced emf , hence according to ohm's law , no induced current (e = IR)

c. The current in the circuit ll be CLOAKWISE around the loop.

d. as we know when current increses . it leads to increse in magnetic field which ll create an indued EMF in circuit. If only current direction is taken into consideration than we should know dat induced current will create a field that opposes magnetic field change.
Here field is incresing out of page, hence induced current ll produce magnetic field INTO page, hence using RIGHT HAND RULE , the current ll be in CLOAKWISE dir around loop....

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