Problem 20.34 A charge of 3.50 ? C is held fixed at the origin. A second charge

ID: 1270409 • Letter: P

Question

Problem 20.34

A charge of 3.50?C is held fixed at the origin. A second charge of 3.50?C is released from rest at the position (1.25 m, 0.570 m).

Part A

If the mass of the second charge is 2.62g , what is its speed when it moves infinitely far from the origin?

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Part B

At what distance from the origin does the second charge attain half the speed it will have at infinity?

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Problem 20.34

A charge of 3.50?C is held fixed at the origin. A second charge of 3.50?C is released from rest at the position (1.25 m, 0.570 m).

Part A

If the mass of the second charge is 2.62g , what is its speed when it moves infinitely far from the origin?

v = m/s

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Part B

At what distance from the origin does the second charge attain half the speed it will have at infinity?

r = m

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a)potential energy of the system initially= Kq1q2/R=80.25*10-3J

this much should be the kinetic energy of the system at infinite distance from origin as at that instant P.E=0

so mv2/2= 80.25*10-3J

substituting the values we get v=7.78m/sec

80.25*10-3J= P.E+K.E

Kq1q2/r+ 20.05*10-3=80.25*10-3J

thus Kq1q2/R= 59.75*10-3J

R=1.84m

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