1. A 2m straight wire carrying 5A current runs horizontally and experienced 8N h

Question

1. A 2m straight wire carrying 5A current runs horizontally and experienced 8N horizontal force while in a 2 T magnetic field. Find direction of the magnetic field with respect to horizontal.

2. An electron is in circular motion with a speed of 2*(10^4) m/s, while in a 40 mT magnetic field, Find the diameter of the circular trajectory.

3. Two 10m parallel wires placed at a distance 0.4m and carrying equal currents attract each other with a force of 2mN. Find the magnitude and direction of the current.

Explanation / Answer

Number 1)

Apply F = BILsin(angle)

8 = (2)(5)(2)(sin(angle)

angle = 23.6o from the horizontal

Number 2)

Apply r = mv/qB

r = (9.11 X 10-31)(2 X 104)/(1.6 X 10-19)(40 X 10-3)

r = 2.84 X 10-6 m

d = 2r = 5.69 X 10-6 m

Number 3)

Apply F/L = uII/2pi(r)

(2 X 10-3)/10 = (4pi X 10-7)(I2)/2pi(.4)

I = 20 Amps

Since they attract, the currents are in the same direction.

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