4) The figure below shows two points in an E-field: Point 1 is at (X1,Y1) = (3,4

ID: 1269351 • Letter: 4

Question

4) The figure below shows two points in an E-field:

Point 1 is at (X1,Y1) = (3,4) in meters, and

Point 2 is at (X2,Y2) = (12,9) in meters.

The Electric Field is constant, with a magnitude of 65 V/m, and is directed parallel to the +X-axis. The potential at point 1 is 1100 V.

(P1)Calculate the potential at point 2.

The coordinates of the points are P1 = (3,4) aNd P2 = (12,9)

The electric field is E = 65 V/m along positive X axis

The potential at P1 is V1 = 1100 V

The electric field can be written as the negative gradient of the potential

P2) If an electron starts from rest at the point (12,0), what is its speed when it reaches (3,0)?

The coordinates of the points are P1 = (3,4) amd P2 = (12,9)

The electric field is E = 65V/m along positive X axis

The potential at P1 is V1 = 1100 V

The electric field can be written as the neagative gradient of the potential

Therefore

E = -?V/?x

?V = -E?x

?V = -(1100 V)(12-3)

?V = -9900 V

Therefore the potential at P2 is

V2 = ?V+V1

V2 = -11000 V

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