deals with the concepts that are important in this problem. As illustrated in th

Question

deals with the concepts that are important in this problem. As illustrated in the figure, a negatively charged particle is released from rest at point B and accelerates until it reaches point A. The mass and charge of the particle are 5.85 x 10-4 kg and -7.02 x 10-5 C, respectively. Only the gravitational force and the electrostatic force act on the particle, which moves on a horizontal straight line without rotating. The electric potential at A is 36.0 V greater than that at B; in other words, VA - VB = 36.0 V. What is the translational speed of the particle at point A?

Explanation / Answer

potential enenrgy = transational KE

q (v2 - v1) = 0.5 m v2

-7.02 * 10-5 * (36.0) = 0.5 * 5.85 * 10-4 * V2

V = 2.94 m/s

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