A bullet with a mass m = 4.83 g and initial speed of 330 m/s passes through a wh
ID: 1267836 • Letter: A
Question
A bullet with a mass m = 4.83 g and initial speed of 330 m/s passes through a wheel which is initially at rest as in the figure. The wheel is a solid disk with mass M = 2.29 kg and radius R = 18.6 cm. The wheel rotates freely about an axis through its center and out of the plane shown in the figure. The bullet passes through the wheel at a perpendicular distance 14.8 cm from the center. After passing through the wheel it has a speed of 232 m/s.
(a) What is the angular speed of the wheel just after the bullet leaves it?
(b) How much kinetic energy was lost in the collision?
BEST ANSWER TO whoever shows ALL steps thanks!
Explanation / Answer
here now conservation of angular momentum plays role
just before collision Angular momentum about Axis passing through center
=.00483*.0148^2*.0148*330
after colllsion
Angular momentum= I*omega+.00483*.0148^2*0148*232=5.16*10^-6
omega=1.527*10^-6/I
omega=3.86 *10^-3 rad/sec
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