What are the strength and direction of the electric field at the position indica
ID: 1267641 • Letter: W
Question
What are the strength and direction of the electric field at the position indicated by the dot in figure?
Part A)
Give your answer in terms of the horizontal and vertical components. Take the positive directions to be up and to the right.
Express your answer using two significant figures. Enter your answers numerically separated by a comma.
Ex, Ey = ________________ N/C
Part B)
Give your answer as a magnitude and angle measured from the positive x-axis.
Express your answer using two significant figures.
E = _____________________ N/C
Part C
Express your answer using three significant figures.
theta = __________________ clockwise from the +x-axis
Explanation / Answer
Part A)
Apply E = kq/r2 for each charge
For the 10nC to the right
E = (9 X 109)(10 X 10-9)/(.04)2
E = 56250 N/C to the left
For the 10 nC in the lower corner, the distance is from the Pyhthagorean Theorem...
r2 = (.04)2 + (.02)2 = .002
The angle is from the tangent function
Tan(angle) = .02/.04
Angle = 26.6o
E = (9 X 109)(10 X 10-9)/(.002)
E = 45000
Ex = 45000(cos 26.6) = 40237 N/C to the left
Ey = 45000(sin 26.6) = 20149 N/C up
For the -5nC at the bottom
E = (9 X 109)(5 X 10-9)/(.02)2
E = 112500 Downward
The net x = 56250 + 40237
Net x = 96487 N/C to the left
Using two sig figs. Ex = 9.6 X 104 N/C left
The net y = 112500 - 20149
Net y = 92351 Downward
Using two sig figs, Ey = 9.2 X 104 N/C Downward
Part B)
Net value is from the Pythagorean Theorem
Net2 = 923512 + 964872
Net = 133560 N/C
Using two sig figs, that is 1.3 X 105 N/C
Part C)
The angle from the tangent formula...
tan(angle) = 92351/96487
Using three sig figs, angle = 224o
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