Four resistors and a battery of negligible internal resistance are assembled to

Question

Four resistors and a battery of negligible internal resistance are assembled to make the circuit in the figure (Figure 1) . The EMF is E = 5.50V , and the resistors are R1 = 4.20? , R2 = 8.60? , R3 = 2.20? , and R4 = 3.90? .

I need the current in R2, R3, and R4. I found it in R1 to be 1.02 A and found the equivalent resistance to be 5.41 ohms. Both of those answers were correct.

Four resistors and a battery of negligible internal resistance are assembled to make the circuit in the figure (Figure 1) . The EMF is E = 5.50V , and the resistors are R1 = 4.20? , R2 = 8.60? , R3 = 2.20? , and R4 = 3.90? . I need the current in R2, R3, and R4. I found it in R1 to be 1.02 A and found the equivalent resistance to be 5.41 ohms. Both of those answers were correct.

Explanation / Answer

Reff = 5.41 ohm

combination of R2 R3 and R4 be Ra

Ra = Reff - R1 = 5.41 - 4.2

Ra = 1.21 ohm

and current in R1 = 1.02 A

current resistance across R2 and R3 and R4 be i2 i3 and i4

V2 = E - i1*R1

V2 = 5.5 - 1.02*4.2

V2 = 1.216 V

V2 = V3 = V4 = 1.216 V as they are in parallel

I2 = V2/R2 = 1.216/8.6 = 0.1414 A

I3 = V3/R3 = 1.216/2.2 = 0.5527 A

I4 = V4/R4 = 1.216/3.9 = 0.3118 A

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