The brass pendulum of an heirloom clock consists of 4.6 inch diameter hollow bra
ID: 1265437 • Letter: T
Question
The brass pendulum of an heirloom clock consists of 4.6 inch diameter hollow brass sphere with a weight of 1.8 pounds attached to the end of a 4.2 ft long brass rod with a weight of 3.3 pounds. The pendulum starts from rest at the angle 43
The brass pendulum of an heirloom clock consists of 4.6 inch diameter hollow brass sphere with a weight of 1.8 pounds attached to the end of a 4.2 ft long brass rod with a weight of 3.3 pounds. The pendulum starts from rest at the angle 43 degree. Determine the following quantities. Mass moment of inertia about the pivot point. (include units with answer)Explanation / Answer
Here ,
the moment of inertia of rod about pivot ,
Irod = ml^2/3
Irod = 3.3 * 4.2^2/3
Irod = 19.4 lb.t^2
now, moment of inertia of sphere about the centre = 0.4 * 1.8 * (4.6/12)^2
Icom = 0.106 lb.ft^2
Now, Using parallel axis theorum ,
moment of inertia of sphere about the pivot
I = Icom = m*d^2
I = 0.106 + 1.8 *(4.2 + 4.6/12)^2
I = 37.92 lb.ft^2
Now, moment of inertia about the pivot of pendulum
Ip = 37.92 + 19.4
Ip = 57.3 lb.ft^2
the moment of inertia about the pivot point is 57.3 lb.ft^2
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