In the figure shown, the equilateral prism is surrounded by air, and the light b
ID: 1265431 • Letter: I
Question
In the figure shown, the equilateral prism is surrounded by air, and the light beam strikes surface 2 at the critical angle. Find the angle of incidence at surface 1, if the index of refraction for the glass prism is 1.45.
a) 27.9 degrees
b) 31.7 degrees
c) 35.6 degrees
d) 21.0degrees
e) 4.2 degrees
In the figure shown, the equilateral prism is surrounded by air, and the light beam strikes surface 2 at the critical angle. Find the angle of incidence at surface 1, if the index of refraction for the glass prism is 1.45. a) 27.9 degrees b) 31.7 degrees c) 35.6 degrees d) 21.0degrees e) 4.2 degreesExplanation / Answer
The critical angle is
Acrit = Arcsin(1/n)
Acrit = 43.6 degrees
Thus, the refracted angle at the first interface is, by some geometry,
Ar = 16.4 degrees
Note that from Snell's law,
n1sin(t1) = n2sin(t2)
where
n1 = index of refraction of first medium = 1.45
t1 = angle of incidence = 16.4 degrees
n2 = index of refraction of second medium = 1
t2 = angle of refraction = degrees
Thus,
t2 = 24.17 degrees [ANSWER]
I wonder why this is not one of the choices. Is there a typo in your choices? I checked it three times.
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