Problem 2: In this problem. 1.00 mol of an ideal diatomic as is heated at consta

Question

Problem 2: In this problem. 1.00 mol of an ideal diatomic as is heated at constant volume from 300 to 600 K. (ci) Find the increase in the internal energy of the gas , the work done by the gas. and the heat absorbed by the gas. (b) Find the same quantities if this gas is bead from OO to (?0 K at constant pressure.. Use the lust law of thermodynamics and your results for (a) to calculate the work clone by the g1s. (c) Again caki1ate the work done in Part (b). This time calculate it by integrating the equation dW - P dV.

Explanation / Answer

a) Internal energy = nCvdT

dU = 1*5/2 R*(600-300)

dU = 6235.5 J

Work done = 0

heat absorbed dQ = dU+dW = dU = 6235.5 J

b) Constant pressure

dU = nCv*dt

dU = 1*(5/2*R)*(600-300)

dU = 6235.5 J

dW = P*dV = nRdT

dW = 1*8.314*300 = 2494.2 J

dQ = dU + dW

dQ = 8729.7 J

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