What is the centripetal acceleration of a bug on the rim of a 11.0-in.-diameter

Question

What is the centripetal acceleration of a bug on the rim of a 11.0-in.-diameter disk if the disk accelerates uniformly from rest to an angular speed of 80.0 rev/min in 4.70 s?

I already found:

tangental acceleration = 0.2489454 m/s^2

tangental velocity = 1.1704066 m/s

I thought that the centripetal acceleration was directly related to the tangental acceleration via:

centripetal acceleration = (tangental acceleration)^2/r? or centripetal acceleration = r^2omega? but when I tried these I'm not getting the correct answer...

Explanation / Answer

centripetal acceleration

a_c = v^2 / r

= ( r w )^2 / r

= r w^2

= (0.2794 m)(80*2*pi /60 s)^2

= 19.6 m/s^2

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