The output piston of a hydraulic press has a cross-sectional area of 0.24 m2. Pa

Question

The output piston of a hydraulic press has a cross-sectional area of 0.24 m2.
Part A How much pressure on the input piston is required for the press to generate a force of 1.6 x 10 to the 6 N?
Part B What force is applied to the input piston if it has a diameter of 4.8 cm? The output piston of a hydraulic press has a cross-sectional area of 0.24 m2.
Part A How much pressure on the input piston is required for the press to generate a force of 1.6 x 10 to the 6 N?
Part B What force is applied to the input piston if it has a diameter of 4.8 cm?
Part A How much pressure on the input piston is required for the press to generate a force of 1.6 x 10 to the 6 N?
Part B What force is applied to the input piston if it has a diameter of 4.8 cm?

Explanation / Answer

Given :

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       Area (A) = 0.24 m2

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       Force applied(F) = 1.6 * 106 N

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(a)   We know that :

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        Preassure (P) = Force / Area = F / A =   1.6 * 106    /0.24 m2    = 6.67 * 106 Pa

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(b)   Diameter (d) = 4.8 *10-2 m

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        Hence radius(r) = 2.4 * 10-2 m  

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        Force applied (F) = P * A   = 6.67 * 106 Pa * ? * (2.4 *10-2 m)2

                                    = 12070 N = 12.070*10^3 N

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