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A steel wire and an aluminum wire of the same length L and diameter d are joined

ID: 1263951 • Letter: A

Question

A steel wire and an aluminum wire of the same length L and diameter d are joined to form a wire of length 2L. The wire is fastened to the ceiling and a mass m is attached to the other end.

The strain in the aluminum portion is ____ the steel portion.

A. depends on how tight m is attached to the steel

B. equal to

C. unable to tell

D. greater than

E. less than

A. depends on how tight m is attached to the steel

B. equal to

C. unable to tell

D. greater than

E. less than

A steel wire and an aluminum wire of the same length L and diameter d are joined to form a wire of length 2L. The wire is fastened to the ceiling and a mass m is attached to the other end. r1-1.png The strain in the aluminum portion is ____ the steel portion. A. depends on how tight m is attached to the steel B. equal to C. unable to tell D. greater than E. less than

Explanation / Answer

Young's Modulus of Aluminium=69 GPa

Young's Modulus of Steel=200 GPa

From above stress is same in both the cases

therefore

E1*Strain1=E2*Strain2   

69*Strain1=200*strain2

Strain1=2.9*Strain2

Hence The strain in the aluminum portion is greater than the steel portion

Option D) is correct

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