2. A heavy box (100. Kg) sits on a horizontal floor. Its square base is 58.3 cm

Question

2. A heavy box (100. Kg) sits on a horizontal floor. Its square base is 58.3 cm on each side and it is 150. cm tall, and it's packed so that its center of mass is at its geometrical center. To move it, you push to apply a horizontal force to its upper edge closest to you, and slowly increase your force until something happens. The coefficient of static friction between the box and the floor is 0.362, and the friction can be taken to act in the middle of the bottom of the box. A) Will the box move horizontally (forces becomes unbalanced) or tip (torques become unbalanced) first? B) what force will you by applying at that time?

Explanation / Answer

here ,

for moving the block ,

Applied force is

Fm = friction

Fm = 100 * g * 0.362

Fm = 354.8 N

the force needed to move is 354.8 N

Now ,

Force needed to trip the box is Ft

Ft * 150 - 100 * g*58.3/2 = 0

Ft = 190.5 N

the force needed to trip is 190.5 N

as force needed to trip is less , hence , the box will trip before moving

b)

The force applied at that time is 190.5 N

Related Questions

Navigate

• Browse (All)
• Browse 2
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.