STILL LOOKING FOR AN ANSWER PLEASE. Find total resistance of both please. Part B

Question

STILL LOOKING FOR AN ANSWER PLEASE.

Find total resistance of both please.

Part B

In the diagram below, resistor values are as follows: Compute the Total Resistance of the circuit (in ohms) and enter it (rounded to the nearest ohm) in the space provided. Do not enter the word ohms - just the numeric value. In the diagram below, resistor values are as follows: Compute the Total Resistance of the circuit (in ohms) and enter it (rounded to the nearest ohm) in the space provided. Do not enter the word ohms - just the numeric value.

Explanation / Answer

Given:

PART -A

If the N no. of resistors are in series we will add resistances:---

Rs=R1+R2+--------RN;

If the N no. of resistors are in parralel we will solve them using formule

1/Rp=1/R1+1/R2+--------1/RN;

Here In 1st figure:

In the upper half of figure:

R2 and R5 are in series

So, RS1 = R2 + R5 = 59 ohm + 92 ohm

RS1 = 151 ohm

Now, RS1 and R4 are in parralel

Resistance is 1/Rp1=1/RS1 + 1/R4

1/Rp1 = 0.00662 +  0.0144

1/Rp1 = 0.02111

Rp1 = 47.359 ohm

Now, R1 and RP1 are in series

RS2 = R1 + RP1

RS2 = 61 + 47.359

RS2 = 108.359 ohm

Now, RS2 and R3 are in parralel

Resistance is 1/Rp2=1/RS2 + 1/R3

1/Rp2 = 1/ 108.359 + 1/51   

1/Rp2 =0.00922 + 0.01960

1/Rp2 =0.028836

Rp2 = 34.678 ohm ---- (1 )

In the Lower half of figure:

Also, R8 and R10 are in series:

RS3 = R8 + R10 = 90 ohm + 75 ohm

  RS3= 165 ohm

Now, RS3 and R7 are in parralel

Resistance is 1/Rp3=1/RS3+ 1/R7

1/Rp3 = 1/165 + 1/ 64

1/Rp3 = 0.00606 + 0.015625

1/Rp3 = 0.02168

Rp3 = 46.1135 ohm

Now R9 and Rp3 are in series

So, RS4 = R9 + Rp3

RS4 = 58 + 46.1135

RS4 = 104.1135 ohm

Now, RS4 and R6 are in parralel

Resistance is 1/Rp4=1/RS4+ 1/R6

1/Rp4=1/104.113 + 1/80

1/Rp4=0.00960 + 0.0125

1/Rp4=0.0221

Rp4 = 45.248 ohm --- (2)

Now, upper half and lower half resistances are in series,

Requivalent = Rp2 + Rp4

Requivalent = 34.678 + 45.248

Requivalent = 79.926 ohm

PART B:-

R2 and R6 are in series

So, RS1 = R2 + R6

RS1 = 82 +64

=> RS1 = 146 ohm

R3 and R4 are in parallel

1/Rp1 =1/R3+1/R4

1/Rp1= 1/ 53 + 1/ 80

1/Rp1= 0.01886 + 0.0125

1/Rp1= 0.03136

=> Rp1 = 31.879 ohm

R7 and R8 are in parallel

1/Rp2 =1/R7+1/R8

1/Rp2 = 1/ 90 + 1/ 82

1/Rp2 = 0.0111 + 0.0121

1/Rp2 = 0.0232

=> Rp2 = 43.08 ohm

Rp1 and Rp2 are in series

RS2 = Rp1 + Rp2

RS2= 31.879 + 43.08

=> RS2 =74.9 ohm

R5 and RS2 are in parallel

1/Rp3 =1/RS2 +1/R5

1/Rp3 = 1/74.9 + 1/73

1/Rp3 = 0.0133 + 0.01369

1/Rp3 = 0.02699

=> Rp3 = 37.050 ohm

Rp3, R1, R9 are in series

RS3 = 37.050 + 78 + 77

=> RS3 =192.05 ohm

RS3 and RS1 are in parallel

1/Requivalent = 1/RS3 +1/RS1

1/Requivalent = 1/192.05 + 1/146

1/Requivalent = 0.00520 + 0.00684

1/Requivalent = 0.01204

=> Requivalent = 83.056 ohm

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