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(a) Determine the length of time it will take an alpha particle to move halfway

ID: 1262898 • Letter: #

Question

(a) Determine the length of time it will take an alpha particle to move halfway around a complete circle.
in s

(b) Does the time found in part (a) increase, decrease, or stay the same, if the speed of the alpha particle is tripled? stay the same

A beam of alpha particles is fired horizontally with a speed of 3.8 x 10^6 m/s. in s x 10^-27 kg. (a) Determine the length of time it will take an alpha particle to move halfway around a complete circle. in s (b) Does the time found in part (a) increase, decrease, or stay the same, if the speed of the alpha particle is tripled? stay the same (c) Repeat part (a) for alpha particles with a speed of 1.1 x 10^5 m/s into a region where there is a vertical magnetic field of magnitude 0.174 T. An alpha particle is the nucleus of a helium atom and as such, consists of two protons, two neutrons, and has a mass of 6.64

Explanation / Answer

When a charged particle enetrs into uniform magnetic field, it moves in a ciruclar motion. so

m v^2 / r = B q v

radius of the circle is

r = m v / B q

= (6.64*10^ -27 kg ) (3.8*10^ 5 m/s) / (0.174 T)(1.6*10^ -19 C)

=0.09 m

Time taken to complete on revolution is

T = 2 pi r / v

= 2 pi ( 0.09 m ) / ( 3.8*10^ 5 m/s)

   =1.5*10^-6 s

Time taken for half circle is 7.44*10^ -7 s

b)

From the above fromula time period is inversely proportional to the speed of the particle and directly proportional to the radius of the circle . so time remains same when the speed increases.

c)

When a charged particle enetrs into uniform magnetic field, it moves in a ciruclar motion. so

m v^2 / r = B q v

radius of the circle is

r = m v / B q

= (6.64*10^ -27 kg ) (1.1*10^ 6 m/s) / (0.174 T)(1.6*10^ -19 C)

=0.262m

Time taken to complete on revolution is

T = 2 pi r / v

= 2 pi ( 0.262 m ) / ( 1.1*10^ 5 m/s)

   =1.48*10^-6 s

Time taken for half circle is 7.44*10^ -7 s