1) Three resistors, 3.30 kohms, 1.05 kohms, and 0.47 k ohms are connected in ser

Question

1) Three resistors, 3.30 kohms, 1.05 kohms, and 0.47 k ohms are connected in series. calculate the equivalent series resistance,

2)  Three resistors, 3.30 kohms, 1.05 kohms, and 0.47 k ohms are connected in parallel. Calculate the equivalent parallel resistance.

3)  Three resistors, 2.00 kohms, 2.50 kohms, and 3.00 k ohms are connected in series. A power supply is connected in the circuit, and applies a voltage of 10.00 V across all three. Calculate the current in the circuit. Enter results in terms of milliamps (mA), where 1mA = 0.001 A.

4) Calculate the voltage drop across the 3.00 kohms resistor in question 3 above.

5) 10.00 volts EMF is applies across three resistors in series, and a current of 1.00 mA is recorded by the current meter in the circuit. A voltage of 4.50 V is measured across the first resistor R1, and a voltage of 2.20 V is measured across the second resistor R2. Find the resistance of the third resistor R3.

Explanation / Answer

For resistances in series

Req = R1 + R2 + R3

for resistances in Parallel ,

1/Req =1/R1 + 1/R2 + ..

Now ,

1)

for series

Req = 3.3 + 1.05 + .47

Req = 4.82 KOhm

2)
In Parallel ,

1/Req = 1/3.3 + 1/1.05 + 1/.47

Req = 0.296 K ohm

3)

Here , in series

Req = 2 + 2.5 + 3

Req = 7.5 K

Now , usinh ohm's law ,

V = IR

I = 10/7.5

I = 1.33 mA

4)

V(3) = 1.33 * 3

V(3) = 4 V

voltage drop across 3 K is 4 V

5)

Here ,

V1 + V2 + V3 = 10

V3 + 4.5 + 2.2 = 10

V3 = 3.3 V

Using ohm's law

R3 = 3.3/1

R3 = 3.3 K

resistance R3 is 3.3 Kohm

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